21q^2-20q+4=0

Solution for 21q^2-20q+4=0 equation:

Simplifying
21q2 + -20q + 4 = 0

Reorder the terms:
4 + -20q + 21q2 = 0

Solving
4 + -20q + 21q2 = 0

Solving for variable 'q'.

Factor a trinomial.
(2 + -7q)(2 + -3q) = 0

Subproblem 1
Set the factor '(2 + -7q)' equal to zero and attempt to solve:

Simplifying
2 + -7q = 0

Solving
2 + -7q = 0

Move all terms containing q to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + -7q = 0 + -2

Combine like terms: 2 + -2 = 0
0 + -7q = 0 + -2
-7q = 0 + -2

Combine like terms: 0 + -2 = -2
-7q = -2

Divide each side by '-7'.
q = 0.2857142857

Simplifying
q = 0.2857142857
Subproblem 2
Set the factor '(2 + -3q)' equal to zero and attempt to solve:

Simplifying
2 + -3q = 0

Solving
2 + -3q = 0

Move all terms containing q to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + -3q = 0 + -2

Combine like terms: 2 + -2 = 0
0 + -3q = 0 + -2
-3q = 0 + -2

Combine like terms: 0 + -2 = -2
-3q = -2

Divide each side by '-3'.
q = 0.6666666667

Simplifying
q = 0.6666666667
Solution
q = {0.2857142857, 0.6666666667}